Question

Two bodies of masses m¹ and m² have equal momenta . Their kinetic energy are in the ratio

Answer and explaination​

Answer 1

Given,

Momentum of m1 = Momentum of m2 = P

So,

K.E. of $m_{1} = \dfrac{P^{2}}{2{m}_{1}}$

K.E. of $m_{2} = \dfrac{P^{2}}{2{m}_{2}}$

Hence, they are in the ratio

$\dfrac{KE_{1}}{KE_{2}} = \dfrac{ \frac{P^{2}}{2m_{1}} }{ \frac{P^{2}}{2{m}_{2}} } = \dfrac{m_{2}}{m_{1}}$