Two bodies of masses M1 and M2, when released near earth's surface
the absence of air take time T1 and T2 to reach the ground respectiv
M1> M2, then
O T1> T2
O 11
О
T1=T2
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Answered by
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Answer:
T1 = T2
Explanation:
in vacuum, every object touch the ground at the same time thus
t1 = t2
but in presence of air , this does not apply
that's why a feather and a ball will drop at ground at different times
Answered by
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Answer:
T1 = T2
Explanation:
As the acceleration due to gravity on both the objects is same that is GMe/R2, so it doesn't depends on mass,acceleration is same on both, both starting from rest, so the time to reach the ground will be same for both the bodies
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