Question

two bodies of masses ma and mb are dropped gently from two different points at height a and b respectively from the ground. The ratio of the kinetic energies of the two bodies when these reach the ground will be

Answer 1

ma.ha:mb.hb is the answer to the question

Answer 2

Explanation:

Let the masses be $M_a$ and $M_b$

Let the heights be $h_a$ and $h_b$

By work power energy theoram

$mgh = \frac{1}{2} m {v}^{2} \\ mgh = kinetic \: energy \\ \\ so \\ ratio \: of \: kinetic \: energy \: will \: be \\ \frac{m_a.h_a}{m_b.h_b}$