Question

Two bodies of same masses are kept at height at h2. What is ratio of their potential engeries.

Answer 1

Answer:

1:2

Explanation:

Potential energy =m×g×h

P.E. of first body =m×g×h

P.E. of second body =m×g×2h

Ratio becomes m×g×h:m×g×2h

Hence ratio of potential energy is 1:2.