two bodies of unequal masses are moving along a straight line with same kinetic energy if the force is applied to stop them are also equal calculate ratio of the distance is covered by them before coming to rest
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Let mass of P be m1
and
Mass of Q be m2
Also
Let time taken by Q be t
thus
Time taken by p = 2t
Similarly
Let distance travelled by Q be x
Thus
distance traveled by P = x/3
velocities
VP = x/3/ 2t = x/ 6t
VQ = x/t
Thus
Ratio of velocities = 1:6
gireeshma7:
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