Question

Two bodies one held 10 m vertically above the other,are released simultaneously. After falling freely for 3 seconds under gravity,their relative separation is freely falling body

Answer 1

Answer:

Now, initial separation =1m

Body 1:

Initial Speed =0

Acceleration =9.8ms

−2

Time =2 seconds

Now, we know that,

s=ut+

2

1

at

2

So, s

1

=

2

1

×9.8×4

s

1

=19.6m

Body 2:

Initial Speed =0

Acceleration =9.8ms

−2

Time =2 seconds

Now, we know that,

s=ut+

2

1

at

2

So, s

2

=

2

1

×9.8×4

s

2

=19.6m

Since s

1

=s

2

so , final separation is also 1m .