Question

Two bodies 'P' and 'Q' are projected horizontally in opposite directions from a tall tower simultaneously with
velocities 10m/sec and 20m/sec. The horizontal distance between them after 2 sec is __m​

Answer 1

Answer:

Explanation:

B

Solution :

v1⋅v2 = 0

⇒(u1+a1t)⋅(u2+a2t)=0

⇒(10

ˆ

i

-10t

ˆ

j

)⋅(-20

ˆ

i

-10t

ˆ

j

)=0

⇒-200+100t2=0

⇒t=

√

2

sec.