Question

two bodies p and q are rubbed in contact and the frictional charge of p is -11.2×10-¹⁴ C.how many electrons are lost or gain by the body q​

Answer 1

Answer:

700000 electrons has transferred

Explanation:

FORMULA :

Number of electrons transferred × charge of electron gives charge acquired.

i.e.,

n×e = q

CALCULATION :-

n × -1.6 × 10E(-19) = -11.2×10E(-14)

n. =. 7 × 10E(5)

n. = 700000 electrons

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