Physics, asked by flashrider, 1 year ago

two bodies p and q having masses m1 and m2 , when separated by distance d1 exerts a force f on each other. what happens when
a)masses of both are doubled.
b)distance between two bodies is reduced to half.
c)the space between the two objects has no air and is complete vacuum.

Answers

Answered by gadakhsanket
129
Hey dear,

◆ Solution-
Gravitational force acting on the bodies is given by -
F = Gm1m2 / r^2

a) When masses are doubled,
F' = G(2m1)(2m2) / r^2
F' = 4Gm1m2 / r^2
F' = 4F

b) When distance is halved -
F' = Gm1m2 / (r/2)^2
F' = 4Gm1m2 / r^2
F' = 4F

c) When medium is complete vacuum,
As gravitational force is independent of intervening medium.
F' = F

Hope this helps you...

Answered by fadimohd34
1

Answer:

Force of Gravitation = (G x m1 x m2)/(d)^2

Force after addition of mass and reduction of distance

= {G x [(2 x M1) x (2 x M2)]}/[(1/2) x d]^2

= 4  x (G x m1 x m2)/ {[(d)^2]/ 4}

= 4 x 4 x (G x m1 x m2)/(d)^2

= 16 x (G x m1 x m2)/(d)^2

Therefore the force will be sixteen times the initial force

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