Two bodies performing shm have same amplitude and frequency
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Two bodies that are performing simple harmonic motion have similar frequency and amplitude. Their phases will be at certain instant will be given in the following image. The phase difference b / w them will be pi / 3.
The solution of this question will be given in the following image .
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Answer:
phase =ϕ
1
sinϕ
1
=0.5A/A=0.5
=0.5
ϕ
1
=π/6
phase =ϕ
2
sinϕ
2
=−0.5 A/A
=−π/6
phase difference =ϕ
1
−ϕ
2
=
3
π
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