Question

Two bodies start moving simultaneously from the same point in the same direction along a straight line. The first body moves with velocity v = 3 m/s, the second with v (6t2 10) m/s. What will be the distance between them in 10 seconds ?

Answer 1

velocity of first body=6m/sec

distance covered by 1st body=x

time=t

6=x/t

velocity of second vehicle=10m/sec

distance covered=(x+40)m

time=t

10=(x+40)/t

x=10t-40

Substituting the value of x,

6=(10t-40)/t

6t=10t-40

40=4t

t=10sec

time=10seconds

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Gadakhsanket ★ Brainly Teacher ★

Hey dear,

◆ Answer-

t = 10 s.

◆ Explaination-

# Given-

v1 = 6 m/s

v2 = 10 m/s

∆s = 40 m

# Solution-

Let s1 and s2 be the distances travelled by two bodies in time t respectively.

s1 = v1t ...(1)

s2 = v2t ...(2)

Substracting-

s2-s1 = v2t - v1t

∆s = (v2-v1)t

40 = (10-6)t

t = 40 / 4

t = 10 s.

Therefore, time required is 10 s.

Hope it helps....