Question

two bodies starts moving from same point along a straight line with velocity 6 m per second and 10 M per second simultaneously after what time their separation becomes 40 meter

Answer 1

velocity of first body=6m/sec
distance covered by 1st body=x
time=t
6=x/t
velocity of second vehicle=10m/sec
distance covered=(x+40)m
time=t
10=(x+40)/t
x=10t-40
Substituting the value of x,
6=(10t-40)/t
6t=10t-40
40=4t
t=10sec
time=10seconds

Hope, this helps you.

Answer 2

Hey dear,

◆ Answer-
t = 10 s.

◆ Explaination-
# Given-
v1 = 6 m/s
v2 = 10 m/s
∆s = 40 m

# Solution-
Let s1 and s2 be the distances travelled by two bodies in time t respectively.
s1 = v1t ...(1)
s2 = v2t ...(2)

Substracting-
s2-s1 = v2t - v1t
∆s = (v2-v1)t
40 = (10-6)t
t = 40 / 4
t = 10 s.

Therefore, time required is 10 s.

Hope it helps....