Question

Two bodies thrown vertically upward with their initial speed ratio 2:3 then what is their ratio in maximum height

Answer 1

Answer:

Two bodies thrown vertically upward with their initial speed ratio 2:3.

Maximum Height covered by the particle is given as

• H = u²/2g

Initial velocity of the body A is 2 m/s and initial velocity of body B is 3 m/s.

$\longrightarrow \: \sf\dfrac{H_1}{H_2}=\dfrac{ \dfrac{u^2}{2g}}{\dfrac{u^2}{2g}}$

$\longrightarrow \: \sf\dfrac{H_1}{H_2}=\dfrac{ \dfrac{(2)^2}{2g}}{\dfrac{(3)^2}{2g}}$

$\longrightarrow \: \sf\dfrac{H_1}{H_2}=\dfrac{ \dfrac{4}{2g}}{\dfrac{9}{2g}}$

$\longrightarrow \: \sf\dfrac{H_1}{H_2}=\dfrac{ 4}{9}$

$\longrightarrow \: \underline{ \boxed{ \bold{\dfrac{H_1}{H_2}=\dfrac{2}{3}}}}$