Question

two bodies whose mass is are in the ratio 2 is to 1 are dropped simultaneously at two places A and B where the acceleration due to gravity g a and g b respectively if they reach the ground simultaneously, ithe ratio of the height from which they are dropped is​

Answer 1

Answer:

Let us start from the basics,

So,

I am assuming the body had a free fall from a height hA and hB respectivley

So,

the potential energy stored will be converted into kinetic energy

So,

(1/2) m v² = mgh

v= √2gh

And,

t=√(2h/g)

So,

we conclude that time taken is independent of the masses

Now they both reached the ground at the same time so,

h = t²g/2

So,

height and gravity acceleration is directly proportional to each other

So,

hA / hB = gA/ gB

This is the required relation.