Question

Two bodies whose masses are in the ratio 2 : 1 are dropped simultaneously
at two places A and B where the accelerations due to gravity are gA and gB
respectively. If they reach the ground simultaneously, the ratio of the
heights from which they are dropped is

Answer 1

Answer:

the ratio of heights from which they are dropped is hA : hB = gA : gB

Explanation:

s = ut + 1/2 a t^2

h = 0 + 1/2 g t^2 as initial velocity is zero

h = 1/2 g t^2

as both bodies reach simultaneously time [t] is same

so, h is directly proportional to g

so, the ratio of heights from which they are dropped is hA : hB = gA : gB

it does not depend on masses since If air resistance is proportional to mass of the body, then acceleration due to it will be independent of mass and hence the two bodies will reach ground simultaneously.