Question

Two bodies with Kinetic Energies in the ratio 2 : 3 are moving with equal momentum. The ratio of their masses will be -

Answer 1

Answer:

Ek=12mv2

Ek=12mv2 The momentum of a particle moving at velocity v is

Ek=12mv2 The momentum of a particle moving at velocity v isp=mv

Ek=12mv2 The momentum of a particle moving at velocity v isp=mvEk=p22m

Ek=12mv2 The momentum of a particle moving at velocity v isp=mvEk=p22mSince p is the same for both particle we have

Ek=12mv2 The momentum of a particle moving at velocity v isp=mvEk=p22mSince p is the same for both particle we haveEk∝1m

Ek=12mv2 The momentum of a particle moving at velocity v isp=mvEk=p22mSince p is the same for both particle we haveEk∝1mhence

Ek=12mv2 The momentum of a particle moving at velocity v isp=mvEk=p22mSince p is the same for both particle we haveEk∝1mhenceEk1Ek2=m2m1

Ek=12mv2 The momentum of a particle moving at velocity v isp=mvEk=p22mSince p is the same for both particle we haveEk∝1mhenceEk1Ek2=m2m1Hence

Ek=12mv2 The momentum of a particle moving at velocity v isp=mvEk=p22mSince p is the same for both particle we haveEk∝1mhenceEk1Ek2=m2m1Hencem1m2=Ek2Ek1=32

Answer 2

Explanation:

Ek=12mv2

The momentum of a particle moving at velocity v is

p=mv

Ek=p22m

Since p is the same for both particle we have

Ek∝1m

hence

Ek1Ek2=m2m1

Hence

m1m2=Ek2Ek1=32