Question

Two bodies with masses m1 and m2 (m1>m2) are joined by a string passing over a fixed pulley. Initially both the blocks are at same time after which two bodies have a separation h is?

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Answer 1

Answer:

here is your answers

Explanation:

Here, we are given that the mass m

1

and m

2

pass over the fixed pulley. So the forces corresponding to the mass m

1

and m

2

are,

m

1

g−T=m

1

a.....(1)

T−m

2

g=m

2

a.....(2)

Adding equations (1) and (2), we get

(m

1

−m

2

)g=(m

1

+m

2

)a

⇒a=(

m

1

+m

2

m

1

−m

2

)g

The downward acceleration =(

m

1

+m

2

m

1

−m

2

)g

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