Question

Two bodies with same mass are moving with the velocities 20 m/s & 15 m/s respectively

before impact and 12 m/s & 15 m/s respectively after impact, determine the value of e.​

Answer 1

Answer:

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Explanation:

a) By momentum conservation, 

2(4)−4(2)=2(−2)+4(ν2)

⟹ν2=1m/s.

b) e=VelocityofapproachVelocityofseparation=4−(−2)1−9−2)=63=0.5

c) At the maximum deformed state, by conservation of momentum, common velocity is ν=0

JD=m2(ν−u2)=4[(0−(−2)]=8Ns

d) Potential energy at the maximum deformed state, 

U= loss in kinetic energy during defirmation

or U=(21m1u12+21m2u22)−21(m1+m2)ν2

=(212(4)2+214