Question

Two bodies X and Y are rubbed together .10¹⁰ electrons move out from X to Y in 10 seconds.How much time is required to transfer 1coulomb of charge to Y?​

Answer 1

Answer:

•Given,

10

9

electron takes 1sec

So, 1 electron takes →

10

9

1

sec

And we know, 1C=6.242×10

18

electron

∴6.242×10

18

electrons takes →

10

9

6.242×10

18

=6.242×10

9

sec

=

60×60×24×365

6.242×10

9

years

=197.93years

≃198years

If 10

9

electrons move out of a body to another body every second, then 198years is required to get a total charge of 1C on the other body.