Question

Two bodies X and Y carry charges -6.6 microC and -5 microC . How many electrons should be transferred from X to Y so that they acquire equal charges?

Answer 1

Heya


$n_{1} e = - 6.6 \times {10}^{ - 3} c$
$n_{2} e = - 5 \times {10}^{ - 3} c$

We know about elementary charge e :

$n_{1} = \frac{ 6.6}{1.6} \times {10}^{16}$

$n_{2} = \frac{5}{1.6} \times {10}^{16}$

Hence, number of electrons in first and second bodies are :

$n_{1} = 4.125 \times {10}^{16}$
$n_{2} = 3.125 \times {10}^{16}$

Average is : 3.625 E 16 electrons

Hence, to acquire equal charge, X should transfer 5 E 15 electrons to Y