Question

two bofies of different masses are dropped from two different heights .What is the ratio of the time taken by the two to drop through this distances​

Answer 1

Answer:

t₁ : t₂ = $\sqrt{h1}:\sqrt{h2}$

Explanation:

Time of flight is independent of the masses of the bodies

Time taken for the drop is given by

t = $\sqrt{(\frac{2h}{g} )}$

$\frac{t1}{t2} =$ $\sqrt{(\frac{2h1}{g} )}$ / $\sqrt{(\frac{2h2}{g} )}$

cancelling out the factors, you are left with

t₁ : t₂ = $\sqrt{h1}:\sqrt{h2}$