Two boint charges Q=5x10↑-6 C and
Q2= 3x10↑-6C are located at point Ą.
(1,3,1)and boint B(3,5,1). Calculate
magnitude of force on Q1, due to
Q2
Answers
Answered by
0
Answer:
Distance between charge
r=root(4+4+0)=root8
Force=k*q1*q2/r^2
=9*10^9*15*10^-12/8
=16.875*10^-3 N
Similar questions
History,
5 months ago
Science,
5 months ago
Social Sciences,
10 months ago
Computer Science,
10 months ago