Question

Two bombs A and B are projected in air. A is thrown with a speed of
30 m/s and B with a speed of 40 m/s as shown in the figure. What is the separation between them after t s ?

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Answer 1

$Vb = \sqrt{30 {}^{2} + 40 {}^{2} } = 50ms {}^{ - 1}$

Time =1sec

Now,

$Sab = Vab \times t$

$= 50 \times 1 = 50m/s$

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