Two bottles contain acid and water in the ratio 2 : 3 and 1 : 2 respectively. These are mixed in the ratio 1 : 3. What is the ratio of acid and water in the new mixture
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Let V Liters of mixture from bottle 1 be mixed with 3 V liters of the mixture from bottle 2.
So in the final mixture we have :
V*2/(2+3) liters of acid and V*3/(2+3) liters of water : from bottle 1
(3V)*1/(1+2) liters of acid and (3V)*2/(1+2) liters of water : from bottle 2
ie., 2V/5 + V liters of acid and 3V/5 + 3V liters of water
7 V/5 litres of acid and 18 V /5 litres of water
Ratio of acid : water = 7 : 18
So in the final mixture we have :
V*2/(2+3) liters of acid and V*3/(2+3) liters of water : from bottle 1
(3V)*1/(1+2) liters of acid and (3V)*2/(1+2) liters of water : from bottle 2
ie., 2V/5 + V liters of acid and 3V/5 + 3V liters of water
7 V/5 litres of acid and 18 V /5 litres of water
Ratio of acid : water = 7 : 18
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