Two boxes A and B were filled with a mixture
of rice and dal-in A in the ratio of 5:3, and in
B in the ratio of 7:3. What quantity must be
taken from the first to form a mixture that
shall contain 6 kg of rice and 3 kg of dal?
Ava
Answers
Given : Two boxes A and B were filled with a mixture of rice and dal-in A in the ratio of 5:3, and in B in the ratio of 7:3.
To Find : What quantity must be taken from the first to form a mixture that shall contain 6 kg of rice and 3 kg of dal
Solution:
6 kg of rice and 3 kg of dal
Total = 9 kg
From A taken = x kg then from B = 9 - x kg
Rice from A = 5x/8
Dal from A = 3x/8
Rice from B = 7(9 - x )/10
Dal from B = 3(9 - x )/10
5x/8 + 7(9 - x )/10 = 6
=> 25x + 28(9-x) = 240
=> 25x + 252 - 28x = 240
=> 3x = 12
=> x = 4
Rice from A = 5x/8 = 2.5
Dal from A = 3x/8 = 1.5
Rice from B = 7(9 - 4 )/10 = 3.5
Dal from B = 3(9 -4 )/10 = 1.5
Hence 4 kg must be taken from the first to form a mixture that
shall contain 6 kg of rice and 3 kg of dal
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