Question

two boys A and B each weighing 600n climb up a rope to a height to 9m. boy A takes 15sec and boy B takes 25sec to accomplish this task what is the power expended by each

Answer 1

hi there!

weight of each boy, mg = 600N
height each of them climb, h = 9m
Time taken by boy A, t1 = 15sec
Time taken by boy B, t2 = 25sec
Power = work done/time taken
Work done, W = mgh = 600×9 = 5400J
Power expended by boy A = W/t1
= 5400/15
= 360 W
Power expended by boy B = W/t2
= 5400/25
= 216 W

hope it helps you....

Answer 2

$p = w \div t$
$p = w \div t \\ for \: a \\ given \: f = 600n \\ d = 9m \\ t = 15s \\ p = 600 \times 9 \div 15 = 360watt \\ forb \\ given \: f = 600 \\ d = 9m \\ t = 25s \\ p = 600 \times 9 \div 25 = 216watt$