Two boys A and B have RS 100 and RS 120 respectively.both together are asked to buy some apples such that the money spend on each apple should be in the ratio 1:2. together how many apples could they purchase?Also identify whether money was totally spent or partially raining with both A and B.cost of a single apple is RS 9.
Answers
Answered by
1
Step-by-step explanation:
Cost price of apple=Rs.20per Kg
∴ cost price of 100kg apples =Rs 100×20
=Rs.2000
5
2
apples of 100 kg =
5
2
×100=40 kgs
Selling price of 40 kg =93 percentage of C.P of 40 kg
=
100
93
×800
=RS.744
Required selling price to get total profit 15percentage
=115 percentage of total cost price
=
100
115
×2000
=RS.2300
∴ Selling price of remaining 60 kg
=Rs.(2300−744)
=Rs.1556
∴ Requried profit =(1556−1200)
=Rs.356
∴ Profit percentage =
1200
356
×100
=29.66percentage
Answered by
0
Answer:
Let number of apples = x. number of oranges = y ,then. number of bananas =100-(x+y). Total cost of fruits = 5x +3y+(100-x-y)/40. 100 = (200x+120y+100-x-y)/40.
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