Two boys A and B of masses 60 kg and 40 kg are standing on a smooth ground at points P and Q of coordination (-10,0,0) & (10,0,0)m. If they move towards Each Other by pulling a common string then they will meet at
1» (-10,0,0)m
2»(0,0,0) m
3» (-2,0,0) m
4» (2,0,0)m
Ans:- (-2,0,0)
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Answered by
53
Answer:The answer is (-2,0,0)
Explanation:As thier is movement in a single dimension, for that particular dimension, if the point at which the meet be y then we have,
Y=(m1y1+m2y2)/(m1+m2)
= (60*(-10)+40*10)/100
= -2
Finally the point at which they will meet is (-2,0,0).
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Answered by
9
Answer:
correct ANSWER is (-2,0,0)
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