Two boys A and B of same height stand on a field facing each other.The see a kite 20meters above their eye level at angle of elevation of 30degree,and 45degree respectively find the distance between the two boys and living your answer in surd.
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tan 30° = 20 / distance from kite to A. [ tan30°= 1/root 3]
1/root 3 = 20/distance from kite to A
distance from kite to A = 20 root 3. (root 3 = 1.73 )
= 20 * 1.73
= 34.9 m
tan 45° = 20 /distance from kite to B [ tan 45°= 1 ]
1 = 20 / distance from kite to B
distance from kite to B = 20
distance of A and B = 20 + 34.9
= 54.9 m or 55 m
1/root 3 = 20/distance from kite to A
distance from kite to A = 20 root 3. (root 3 = 1.73 )
= 20 * 1.73
= 34.9 m
tan 45° = 20 /distance from kite to B [ tan 45°= 1 ]
1 = 20 / distance from kite to B
distance from kite to B = 20
distance of A and B = 20 + 34.9
= 54.9 m or 55 m
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