Physics, asked by bhumiani1234, 10 months ago

Two boys A and B , travel along the same path . The displacement- time graph for their journey is given in the following figure

Answers

Answered by Blaezii
17

Answer:

Please try to post the complete question.

I have attached the question as attachment.

Correct Answer :

1A] When A starts his journey at 4 sec , B has has already covered a distance of 857m.

B] A travels fatser than B because A starts his journey late but crosses B and covers more distance.

C] Speed of A=Distance/timeAt t=12min, distance covered=3500m=3500/12=375m/min

D] Speed of B=3000/12=214m/min

E] Speed of approach of A towards B=375m/min -214 m/min=161 m/min

F] Speed of seperation of A from B=161m/min.

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bhumiani1234: But how 857 m
bhumiani1234: How 857m
bhumiani1234: Thanks
bhumiani1234: In question where is 857 m
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