Two boys A and B , travel along the same path . The displacement- time graph for their journey is given in the following figure
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1A] When A starts his journey at 4 sec , B has has already covered a distance of 857m.
B] A travels fatser than B because A starts his journey late but crosses B and covers more distance.
C] Speed of A=Distance/timeAt t=12min, distance covered=3500m=3500/12=375m/min
D] Speed of B=3000/12=214m/min
E] Speed of approach of A towards B=375m/min -214 m/min=161 m/min
F] Speed of seperation of A from B=161m/min.
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bhumiani1234:
But how 857 m
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