Two boys A and B travel along the same path the displacement time graph for thier journey is given in the following figure
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Answered by
169
Please try to post the complete question.
I have attached the question as attachment.
Correct Answer :
1A] When A starts his journey at 4 sec , B has has already covered a distance of 857m.
B] A travels fatser than B because A starts his journey late but crosses B and covers more distance.
C] Speed of A=Distance/timeAt t=12min, distance covered=3500m=3500/12=375m/min
D] Speed of B=3000/12=214m/min
E] Speed of approach of A towards B=375m/min -214 m/min=161 m/min
F] Speed of seperation of A from B=161m/min.
I have attached the question as attachment.
Correct Answer :
1A] When A starts his journey at 4 sec , B has has already covered a distance of 857m.
B] A travels fatser than B because A starts his journey late but crosses B and covers more distance.
C] Speed of A=Distance/timeAt t=12min, distance covered=3500m=3500/12=375m/min
D] Speed of B=3000/12=214m/min
E] Speed of approach of A towards B=375m/min -214 m/min=161 m/min
F] Speed of seperation of A from B=161m/min.
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Answered by
86
Prmkulk1978 you have missed some points
E )- yes speed of A and B are uniform
F )- Point x represent the point where the ( A nd B ) meet during their journey
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