two boys are selling oranges .one of the has 9oranges more than the other and it is 56%of the total number of orange.the oranges each boy has is?????
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Let total no. of oranges be x
A.T.Q
No. of oranges with 1st person = 56/100x
No. of oranges with 2nd person = 44/100x
56/100x + 44/100x = 100
( 56x + 44x )/100 = 100
100x / 100 = 100
x = 100
Therefore; the total no. of oranges are 100
No. of oranges with 1st boy = 56
No. of oranges with 2nd boy = 44
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A.T.Q
No. of oranges with 1st person = 56/100x
No. of oranges with 2nd person = 44/100x
56/100x + 44/100x = 100
( 56x + 44x )/100 = 100
100x / 100 = 100
x = 100
Therefore; the total no. of oranges are 100
No. of oranges with 1st boy = 56
No. of oranges with 2nd boy = 44
Hope it hepls ✌✌✌✌!!!!!!
please mark it as brainliest.....
#follow
zombiehordes18:
why
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2
Answer:
42,33
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