Question

Two boys are standi5 at the ends A and B of a ground where AB equals to a . The boy at B starts running in a direction perpendicular to AB with velocity v1 .The boy at A starts running simultaneously with velocity v and catches the other boy in time t where t is

Answer 1

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Answer 2

Answer:

t = $\frac{a^{2} }{(V^{2}-V_{1}^{2} )}$

Explanation:

Distance covered by boy A in time t ⇒ AC = Vt

Distance covered by boy B in time t ⇒ BC = V₁t

Using Pythagoras Theorem :

⇒ AC² = AB² + BC²

⇒ (Vt)² = a² + (V₁t)²

⇒ a² = V²t² - V₁²t²

⇒ a² = t²(V²-V₁²)

⇒ t² = a²/ (V²-V₁²)

∴ t = $\frac{a^{2} }{(V^{2}-V_{1}^{2} )}$