Question

Two boys each of mass 50 kg are sitting on a bench and the separation between them is 0.5 metre what is the magnitude of gravitational force between them?(G=6.67×10^11 N m^2 kg^-2) *
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Answer 1

Answer:

let's M1 is equals to 50 kg and M2 is equals to 50 kg

distance between two masses is 0.5 m

universal gravitational constant=6.67*10^-11 Nm^2 kg^2

F=G*m1m2/(d)^2

=6.67*10^-11*50*50/0.5*0.5

=6.67*10^-7