Question

Two boys P and Q are running along the same path. P is 10, a head of Q initially. However, Q catches up with p. after running 50m. Assuming that both boys are running at a constant speed. what is the ratio of speeds of p and Q​

Answer 1

Answer:

The ratio between the speeds of the two boys=Q: P=5:1

Explanation:

Let us imagine P is at point x.

Similarly, Q is at point y.

P is 10 ahead of Q.

After running 50m Q catches up with P.

It means P was 5m (50/10) ahead of Q.

If both the boys were running at a constant speed then:

5P = Q

Hence the ratio between the speeds of the two boys is:

Q:P

=5:1

Answer 2

Two boys P and Q are running along the same path. P is 10 m ahead of Q initially. However Q catches up with P, after running 50 m. assuming that both boys are running at a constant speed what is the ratio of the speeds of P and Q?

$Let \: the \: speed \: of \: P = x \: m/s \\ Let \: the \: speed \: of \: Q = y \: m/s \\ Suppose \: they \: meet \: after \: t \: seconds \\ at \: a \: point \: which \: is \: at \: a \: distance \: of \\ 50 \: m \: from \: Q\: and \\ 40 \: m \: from \: P. \\ now, \: speed = \frac{distance}{time} \\ So, x = \frac{40}{t} \: and \: y = \frac{50}{t} \\ Now, \: xy = \frac{ \frac{40}{t} }{ \frac{50}{t} } = \frac{40}{50} = \frac{4}{5}$