Two boys raising a bucket pull it at an angle 0 to each other. If each exerts a force of 20 N and their effective pull is 30 N, what is the angle between their arms ? Ans. 82° 49'1
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Answer:
hi
Explanation:
Let the force exerted be A and their effective pull be B.
Here, A = 20N, B = 20N, R = 30θ= ?
using R=√A^2 + B^2 + 2ABcosθ
Now, we have 30^2 = 20^2 + 2×20×20cosθ
or cosθ 30^2−20^2−20^2/2×20×20=0.125
or theta = 82^249'.
I hope this information helps you.
Good Luck
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