Question

Two boys sat for an examination. One of them got 9 marks more than the other and his marks were 56% of their marks. Find the marks scored by each.​

Answer 1

Answer:

hu

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Marks of first student = M (say)

Then, marks of second student = M+9

Given that, the marks of second student (M+9) is 56% of the sum of both the students marks.

Sum = M+ M+9 =2M+9

Therefore,

(Second student marks/ sum) *100= 56%

( (M+9)/(2M+9) ) *100 = 56

Upon solving cross multiplying and solving for M,

We have,

(M+9)=0.56*(2M+9)

=> M+9= 1.12M + 5.04

=> 9- 5.04 = 1.12M - M

=> 3.96 = 0.12M

=> M= 3.96 /0.12

=> M=33; M+9= 42

Marks obtained by first student is 33.

Marks obtained by second student is 42