Two boys start running towards each other from two points, they are 300 m apart. One runs with
a speed of 10 m/s and other with a speed of 20 m/s. When and where do they meet each other
from the initial position of the boy moving with the speed of 10 m/s
Answers
Answered by
4
Answer:
AB=10*t. BC=30-x=20*t
x=10t. 300-x=20*t
300=30
t=10
x=100
Answered by
0
Answer:
Step-by-step explanation:
AB=10*t. BC=30-x=20*t
x=10t. 300-x=20*t
300=30
t=10
x=100
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