Question

Two boys start running towards each other from two points, they are 120 m apart. One runs with a

speed of 5 m/s and other with a speed of 7 m/s. When and where do they meet each other from first

point.

1) 10 s, 50 m 2) 10 s, 70 m 3) 24s, 50 m 4) 17 s, 70 m​

Answer 1

Answer:

Explanation:

Let the two boys meet after t sec their start.

So

5t+7t=100

⇒t=10012=253 s

The distance of meeting point is 253×5=1253 m apart from the starting point of slower boy.