Question

two brands of chocolates are available in pack of 24 and 15 respectively. if I need to buy an equal number of chocolates of both kinds, what is the least number of boxes of each kind I would need to buy?​

Answer 1

Answer:

Given:- Two brands of chocolates are available in packs of 24 and 15 respectively.

To Find:- the least number of boxes so that equal number of both kind of chocolates can be bought, we need to find LCM of 24 and 15.

so,

$24 = 2 \times 2 \times 2 \times 3 \: \textbf{and} \times 15 = 3 \times 5$

$\textbf{LCM of \: } 24, 15 = 2 \times 2 \times 2 \times 3 \times 5 = 120$

so,

‣number of packets to be bought of first brand

$⇒ \frac{120}{24} = 5$

‣and, number of packets to be bought of second brand

$⇒ \frac{120}{15} = 8$

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