Two brands of chocolates are available in packs of 24 and 15 respectively. If in need to but an equal number of chocolates of both kinds, what is the least number of boxes of each kind i would need to buy?
Answers
Answer: 5 and 8
Step-by-step explanation:
Take LCM of 24 and 15 which comes out to be 120
So you need 120 chocolates of each brand.
Now numbers of packs of first chocolate= 120/24 = 5
120/15 = 8
SOLUTION :
Given :
Number of chocolates of 1st brand in one pack = 24
Number of chocolates of 2nd brand in one pack = 15.
To find the least number of boxes of each kind first we have to find the LCM of 24 and 15.
LCM by prime factorization method :
24 = 2 x 2 x 2 x 3
15 = 3 × 5
L.C.M. of 24 and 15 = 2 x 2 x 2 x 3 x 5
[LCM of two or more numbers = product of the greatest power of each prime factor involved in the numbers, with highest power.]
L.C.M. (24,15) = 120
Hence, the number of packets of 1st brand = 120/24 = 5
number of packets of 2nd brand = 120/15 = 8
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