two brands of chocolates are available in packs of 24 and 15 respectively if I need to buy an equal number of chocolates of both kinds what is the least number of boxes of each kind I would need to buy
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Answered by
951
Given, two brands of chocolates are available in pack of 24 and 15 respectively.
We need to buy an equal number of chocolates of both kinds.
For this we find the LCM of 24 and 15
Now, 24 = 2 * 2 * 2 * 3
and 15 = 3 * 5
LCM(24, 15) = 2 * 2 * 2 * 3 * 5 = 120
Now, the number of boxes of pack of 24 = 120/24 = 5
and the number of boxes of pack of 15 = 120/15 = 8
I hope it will be useful for you to understand
if yes means please mark it as brainliest answer
thank you!!!
We need to buy an equal number of chocolates of both kinds.
For this we find the LCM of 24 and 15
Now, 24 = 2 * 2 * 2 * 3
and 15 = 3 * 5
LCM(24, 15) = 2 * 2 * 2 * 3 * 5 = 120
Now, the number of boxes of pack of 24 = 120/24 = 5
and the number of boxes of pack of 15 = 120/15 = 8
I hope it will be useful for you to understand
if yes means please mark it as brainliest answer
thank you!!!
Answered by
293
:For this we find the LCM of 24 and 15
Now, 24 = 2 * 2 * 2 * 3
and 15 = 3 * 5
LCM(24, 15) = 2 * 2 * 2 * 3 * 5 = 120
Now, the number of boxes of pack of 24 = 120/24 = 5
and the number of boxes of pack of 15 = 120/15 = 8
Mark it as brainlist
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