Two breakers are kept on a table. the capacity of the first breaker is x liters and that of the second breaker is 2x. two thirds of the 1st breaker and one fourth of the 2nd breaker is filled with wine. the remaining space in both breakers is filled with water. if the content in these breakers are mixed in a larger breaker of volume 3x, what is the proportion of wine in the breaker?
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Capacity of Breaker A = x
Capacity of Breaker B = 2x
Find the total amount of wine:
2/3 of the Breaker A = 2/3 (x) = 2x/3
1/4 of the Breaker B = 1/4 (2x) = 2x/4 = x/2
Total = 2x/3 + x/2 = 7x/6
Find the amount of water:
Water = 3x - 7x/6 = 11x/6
Find the ratio:
Wine : Water = 7x/6 : 11x/6
Multiply by 6:
Wine : Water = 7x : 11x
Divide by x:
Wine : Water = 7 : 11
Find the fraction of wine:
Wine = 7 / ( 7 + 11) = 7/18
Answer: 7/18 of the content is wine
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