two brothers jam and jin together have 56 Marbles both of them lose 6 Marble each and the product of the number of Marbles in now have as 475
Answers
Answered by
1
Let Jam and Jin have x and y marbles respectively.
Case 1: x+y=56 .............(1)
Case 2:(x-6)×(y-6)=475
xy-6x-6y+36=475
xy-6(x+y)+36=475
xy-6×56+36=475. [From eq.(1)]
xy-336+36=475
xy-300=475
xy=475+300
xy=775 .......................(2)
then,(x-y)^2=(x+y)^2-4×xy
=(56)^2 - 4×775. [From eq. (1)&(2)]
=3136-3100
=36
so,x-y=√36
x-y=6 ..................(3)
On adding eq. (1)& eq. (3),
2x=62
x=31
Put x=31 in eq. (1),
31+y=56
y=25
Thus,Jam and Jin have 31 and 25 marbles respectively.
Case 1: x+y=56 .............(1)
Case 2:(x-6)×(y-6)=475
xy-6x-6y+36=475
xy-6(x+y)+36=475
xy-6×56+36=475. [From eq.(1)]
xy-336+36=475
xy-300=475
xy=475+300
xy=775 .......................(2)
then,(x-y)^2=(x+y)^2-4×xy
=(56)^2 - 4×775. [From eq. (1)&(2)]
=3136-3100
=36
so,x-y=√36
x-y=6 ..................(3)
On adding eq. (1)& eq. (3),
2x=62
x=31
Put x=31 in eq. (1),
31+y=56
y=25
Thus,Jam and Jin have 31 and 25 marbles respectively.
Similar questions