two bugs A and B are travelling along a meter scale A and B are at 50 cm and 40 cm respectivilely after 2minutes they are at 40 cm and 25 cm marks respectively time required for bug A travel from 50 cm mark to 25 cm mark is
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Distance travelled by bug A in 2 minutes is
(50−40)=10 cm and Distance travelled by
bug B in 2 minutes is (40−25)=15 cm
speed of bug A=10/2=5 cm/min .
Now distance travelled by bug A is
(50−25)=25 cm
So time required by bug A=525=5 min
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