two building of height 26 m and 14 m are exactly on opposite sides of a road . If the distance between their tops is 15 m find the width of the road
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Well The height given are 26m and 14m and since one is longer than the other pole, it would make a right-angled triangle
Then you can use Pythagoras theorem to find the distance b/w them
Then you can use Pythagoras theorem to find the distance b/w them
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Height of building1(b1)=26m
Height of building2(b2)=14m
Distance between the heights(BC)15m
Difference between b1 and b2(AC)=26-14=12m
Therefore, using Pythagoras theorem,
AB*AB +AC*AC=BC*BC
here, AB is the width.
Hence, AB*AB=BC*BC-AC*AC
=15*15-12*12=81
Since AB*AB =81, AB=9m.
The width of the road is 9 meters.
Height of building2(b2)=14m
Distance between the heights(BC)15m
Difference between b1 and b2(AC)=26-14=12m
Therefore, using Pythagoras theorem,
AB*AB +AC*AC=BC*BC
here, AB is the width.
Hence, AB*AB=BC*BC-AC*AC
=15*15-12*12=81
Since AB*AB =81, AB=9m.
The width of the road is 9 meters.
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