Question

Two buildings 22 m and 30 m high stand up right on a ground. If they are 15 m apart, the distance between their tops is -----------

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

17m

Step-by-step explanation:

now the height of first building AB= 22m

height of second building DC = 30 m

thus, the difference between their hights (AE) = 30-22 = 8

the horizontal distance between two buildings (BC) = 15m

ABCE form a rectangle, thus AE = BC = 15m

now, triangle AED is right angle triangle with angles E=90°

using Pythagoras theorem ,

AD^2 = (AE^2) + (DE^2)

= (15^2) + (8^2)

= 225 + 64

= 289

AD = √289

= 17m