Question

Two buildings
A
and
B
are as shown in the diagram.
A
woman walks out of building
B
to get some sunshine. How much minimum distance in metres will she have to walk in the right direction of building
B
, according to the situations given below? Assume the right direction of buildings as positive and ground as
X
−
a
x
i
s
.

Answer 1

Answer:

Answer is 37.5m.

Step-by-step explanation:

Calculate the two angles.

Then with those angles find distance the woman walked.

Note:

62.5m is the total distance from base of block A to the point woman get's sunray. i.e. 25 + 37.5 = 62.5

Answer 2

Given : two building a and b a woman walks out of building b to get some sunshine

First sunray blocked by building A is also the first sunray blocked by building B

To Find : how much min distance will she have to walk in right direction of building b

Solution:

Let say Woman has to walk  x  meter

as Buildings are parallel  

so Two similar triangles are formed

Hence  x / ( x + 25)  = 30/50

=> x/(x + 25) = 3/5

=> 5x = 3x + 735

=> 2x  = 75

=> x = 37.5

Woman has to walk 37.5 m

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