Question

Two buildings are 20 m and 24 meters high respectively, if the horizontal distance between the two buildings is 3 meters, find the distance between the two tops​

Answer 1

Answer:

From the diagram, PB=CD=12 m

AP=AB−PB=(22−12) m=10 m

Also CP=BD=24 m

Since △APC is a right angled triangle,

AC

2

=AP

2

+PC

2

AC

2

=10

2

+24

2

AC

2

=676

∴AC=26 m

Hence, distance between their tops is 26 m.