Two buildings are 20m and 25m high. If the buildings are 12m apart, find the distance between their tops
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Answered by
90
from the given diagram:
by pythagoras theorem,
distance between tops=(5^2+12^2)^1/2
=(25+144)^1/2
=169^1/2=13
therefore,distance b/w their tops is 13 m.
by pythagoras theorem,
distance between tops=(5^2+12^2)^1/2
=(25+144)^1/2
=169^1/2=13
therefore,distance b/w their tops is 13 m.
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Answered by
27
According to the given diagram
Step-by-step explanation:
In the diagram BE=CD=20m
then AC=5m
BC=ED=12cm
Pythagoras theorem says
{hypotenuse}² = {base}² + {perpendicular}²
so AB²=AC²+BC²
=25+144
=169
AB=√169
AB=13m
Therefore distance between their top is 13m.
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